Solutions of system differential equations-the total response of the system
2-2 Solutions of system differential equations-total response of the system | |||
1. Proof of linearity of linear differential equations | |||
The linear system must satisfy both homogeneity and superposition. Therefore, to prove whether the differential equation of a linear system is linear, we must prove whether it satisfies both homogeneity and superposition. The general form of the differential equation of a linear system is | |||
(2-5) | |||
Assuming that the solution of this equation to the input f1 (t) is y1 (t), then | |||
(2-6) | |||
If the solution of the equation to the input f2 (t) is y2 (t), then | |||
(2-7) | |||
Multiply both ends of the equal sign of formula (2-6) by an arbitrary constant A1, and multiply both ends of equal sign of formula (2-7) by an arbitrary constant A2, then have | |||
Add these two forms and you have | |||
This means that if f1 (t) | |||
Second, the solution of the system differential equation-the total response of the system | |||
Seeking a solution to the system's differential equations is actually seeking the system's full response y (t). The solution of the system differential equation is the total response y (t) of the system. The full response y (t) of a linear system can be decomposed into the superposition of zero input response yx (t) and zero state response yf (t), ie | |||
In Figure 2-2, if the excitation f (t) = 0, but the initial condition of the system is not equal to zero, then the system response is the zero input response yx (t), as shown in Figure 2-4 (a). According to equation (2-5), the differential equation of the system at this time is written as: | |||
(2-8) | |||
In Figure 2-2, if the incentive | |||
(2-9) | |||
Add formula (2-8) and formula (2-9) | |||
which is | |||
In the formula | |||
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